2x^2+7x-774=0

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Solution for 2x^2+7x-774=0 equation:



2x^2+7x-774=0
a = 2; b = 7; c = -774;
Δ = b2-4ac
Δ = 72-4·2·(-774)
Δ = 6241
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6241}=79$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-79}{2*2}=\frac{-86}{4} =-21+1/2 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+79}{2*2}=\frac{72}{4} =18 $

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